单行指向Linestring

作者: 那年
发布时间: 2025-01-30 04:12:53 (12小时前)
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诸葛神侯 | 2019-08-31 10-32

<div class =“post-text”itemprop =“text”> <P> 这是一个解决方案 </p> <pre> <code> from shapely.geometry import Point, LineString o = [Point (-116.2847753565571, 43.61722615312507), Point(-116.2847753565571, 43.61722615312507), Point (-116.2847753565571,43.61722615312507)] d = [Point (-116.3042144501943, 43.60844476082184), Point(-116.3042144501943,43.60844476082184), Point(-116.3042144501943,43.60844476082184)] df = pd.DataFrame({'orig_coord' : o, 'dest_coord': d}) df['line']=df.apply(lambda x: LineString([x['orig_coord'], x['dest_coord']),axis=1) print(df['line']) </code> </pre> </DIV>

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土豆 | 2019-08-31 10-32

<div class =“post-text”itemprop =“text”> <P> 我已经用它来获取Point对象，但我没有想过要重复这个过程： </p> <P> <code> df['line']=[LineString(xy) for xy in zip(df.orig_coord,df.dest_coord)] </code> </p> </DIV>

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