PROSAGA码农传奇-titan-如何“连接”顶点及其边数作为JanusGraph或Gremlin中这些顶点的“属性”？

如何“连接”顶点及其边数作为JanusGraph或Gremlin中这些顶点的“属性”？

作者: trpnest
发布时间: 2025-01-21 01:23:23 (23天前)
转自：

<div class =“post-text”itemprop =“text”>
  <P>
    以TinkerPop的现代玩具图为例，你可以这样做：
  </p>
   <pre>
    <code>
      gremlin> g.V().as('a').
......1>   map(outE('created').count()).as('count').
......2>   select('a','count').by(valueMap()).by()
==>[a:[name:[marko],age:[29]],count:1]
==>[a:[name:[vadas],age:[27]],count:0]
==>[a:[name:[lop],lang:[java]],count:0]
==>[a:[name:[josh],age:[32]],count:2]
==>[a:[name:[ripple],lang:[java]],count:0]
==>[a:[name:[peter],age:[35]],count:1]

</code>
  </pre>
  <P>
    它返回“a”中顶点的属性和“created”边的计数。您也可以选择使用
     <code>
      project()
    </code>
    ：
  </p>
   <pre>
    <code>
      gremlin> g.V().
......1>   project('a','knows','created').
......2>     by(valueMap()).
......3>     by(outE('knows').count()).
......4>     by(outE('created').count())
==>[a:[name:[marko],age:[29]],knows:2,created:1]
==>[a:[name:[vadas],age:[27]],knows:0,created:0]
==>[a:[name:[lop],lang:[java]],knows:0,created:0]
==>[a:[name:[josh],age:[32]],knows:0,created:2]
==>[a:[name:[ripple],lang:[java]],knows:0,created:0]
==>[a:[name:[peter],age:[35]],knows:0,created:1]

</code>
  </pre>
</DIV>