如何修改我的代码以在外部打印变量，这是在try-catch中初始化的？

不要试图打印try / catch之外的平均值;最后将它打印在try块内。当抛出异常时，您不想打印平均值。用户输入错误，即使您可以打印它，计算也将无效。

    
      try {
    i0 = scan.nextDouble();
    i1 = scan.nextDouble();
    i2 = scan.nextDouble();
    i3 = scan.nextDouble();
    i4 = scan.nextDouble();
    i5 = scan.nextDouble();
    i6 = scan.nextDouble();
    i7 = scan.nextDouble();
    i8 = scan.nextDouble();
    i9 = scan.nextDouble();
    double isum = i0 + i1 + i2 + i3 + i4 + i5 + i6 + i7 + i8 + i9;
    double iresult = isum / 10;
System.out.println("The average of all the 10 numbers is " + isum);
} catch (InputMismatchException e) {
    System.out.println(e + “\nPlease, enter only numbers.”);
}
</code>
  

如果有例外，将不会有任何结果，所以我会打印出来

try

块。另外，根据您的print语句，您要打印结果（而不是总和）。

    
          double iresult = isum / 10;
    System.out.println(“The average of all the 10 numbers is “ + iresult);
} catch (InputMismatchException e) {
    System.out.println(e + “\nPlease, enter only numbers.”);
}
</code>
  

您需要在try块中移动平均值的打印作为

isum

变量只能在。中访问

try

块。请尝试以下代码

    
      import java.util.*;
public class QuestionOne {
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        double i0, i1, i2, i3, i4, 
i5, i6, i7, i8, i9;
System.out.println("Please enter a number for each input.");
try {
    i0 = scan.nextDouble();
    i1 = scan.nextDouble();
    i2 = scan.nextDouble();
    i3 = scan.nextDouble();
    i4 = scan.nextDouble();
    i5 = scan.nextDouble();
    i6 = scan.nextDouble();
    i7 = scan.nextDouble();
    i8 = scan.nextDouble();
    i9 = scan.nextDouble();
    double isum = i0 + i1 + i2 + i3 + i4 + i5 + i6 + i7 + i8 + i9;
    double iresult = isum / 10;
    System.out.println("The average of all the 10 numbers is " + isum);
} catch (InputMismatchException e) {
    System.out.println(e + "\nPlease, enter only numbers.");
}
 }
}
</code>