按字母数字排序数组

作者: 甲基蓝
发布时间: 2024-11-07 11:44:20 (5天前)
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石茶 | 2019-08-31 10-32

<div class =“post-text”itemprop =“text”> <P> 简单地使用 <code> .sort() </code> 。 </p> <P> </p> <div class =“snippet”data-lang =“js”data-hide =“false”data-console =“true”data-babel =“false”> <div class =“snippet-code”> <pre class="snippet-code-js lang-js prettyprint-override"> <code> var items = [ "NFO:BANKNIFTY1931428900CE", "NFO:BANKNIFTY1931429000CE", "NFO:BANKNIFTY1931429500CE", "NFO:BANKNIFTY1931429400CE", "NFO:BANKNIFTY1931429300CE", "NFO:BANKNIFTY1931429200CE" ] var sorted = items.sort() console.log(sorted); </code> </pre> </DIV> </DIV> <P> </p> </DIV>

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IP地址 | 2019-08-31 10-32

<div class =“post-text”itemprop =“text”> <P> 通过字母数字方式使用排序数组 <code> localeCompare </code> 方法。 </p> <P> 该的<strong> localeCompare（） </强> method返回一个数字，指示引用字符串是在排序顺序之前还是之后出现，或者与排序顺序中的给定字符串相同。 </p> <P> </p> <div class =“snippet”data-lang =“js”data-hide =“false”data-console =“true”data-babel =“false”> <div class =“snippet-code”> <pre class="snippet-code-js lang-js prettyprint-override"> <code> const sortAlphaNum = (a, b) => a.localeCompare(b, 'en', { numeric: true }) console.log([ "NFO:BANKNIFTY1931428900CE", "NFO:BANKNIFTY1931429000CE", "NFO:BANKNIFTY1931429500CE", "NFO:BANKNIFTY1931429400CE", "NFO:BANKNIFTY1931429300CE", "NFO:BANKNIFTY1931429200CE" ].sort(sortAlphaNum)) </code> </pre> </DIV> </DIV> <P> </p> </DIV>

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