PROSAGA码农传奇-Sahara云大数据-如何通过工作表单验证将html与php分开

如何通过工作表单验证将html与php分开

作者: 一瓶泡沫
发布时间: 2025-02-28 12:55:15 (4天前)
转自：

<div class =“post-text”itemprop =“text”>
  <P>
    你不能在html文件中执行php代码。所以，将form.html文件扩展名设为form.php
如果发生错误，从process.php重定向到form.php时传递一个get参数。
  </p>
  <P>
    检查form.php中是否有get参数然后呈现消息。
  </p>
   <pre>
    <code>
             if($arrmessage =="")
        {       
            $student_name = $_POST['student_name']; 
            $email = $_POST['email'];
            $contact_number = $_POST['contact_number'];
            $gender = $_POST['gender'];
            $interest = $_POST['interest'];
            $checked ="";
            foreach($interest as $list){$checked .= $list .",";}
            $DOB = $_POST['day'].'-'.$_POST['month'].'-'.$_POST['year'];
            $street_adress = $_POST['street_adress'];
            $city = $_POST['city'];
            $state = $_POST['state'];
            $country = $_POST['country'];

$sql = "INSERT INTO form (student_name,email,contact_number,gender,interest,DOB,street_adress,city,state,country)VALUES('{$student_name}','{$email}','{$contact_number}','{$gender}','{$checked}','{$DOB}','{$street_adress}','{$city}','{$state}','{$country}')";
        mysql_query($sql);
        if(mysql_insert_id() != ""){
                echo "Records inserted successfully.";
                }
                header("Location:views.php");
                exit;
         } else {
                 header("Location:form.php?error=1&msg=$arrmessage");
         }

</code>
  </pre>
  <P>
    在form.php文件中你需要检查get if $ _GET ['error']然后显示你在$ _GET ['msg']中得到的消息
  </p>
</DIV>