Matplotlib极坐标绘图：以度为单位显示极坐标，带十进制格式

作者: 解天
发布时间: 2024-06-20 10:55:09 (1月前)
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AsuRa | 2019-08-31 10-32

<div class =“post-text”itemprop =“text”> <P> 极地图的内部单位是辐射。因此，在辐射中给出了刻度的位置，这些是你需要格式化的数字。你可以用一个 <code> FuncFormatter </code> 。 </p> <pre> <code> rad2fmt = lambda x,pos : f"{np.rad2deg(x):.2f}锟斤拷" ax.xaxis.set_major_formatter(FuncFormatter(rad2fmt)) </code> </pre> <P> 完整的示例如下所示： </p> <pre> <code> import numpy as np import matplotlib.pyplot as plt from matplotlib.ticker import FuncFormatter minTheta = 0.42; maxTheta = 0.55 fig = plt.figure() ax = fig.add_subplot(111, projection='polar') #create four tick labels (in radians) dynamically based on the theta range ticks = np.linspace(minTheta, maxTheta, 4) ax.set_xticks(ticks) #disable or enable the following line to change the tick display format* rad2fmt = lambda x,pos : f"{np.rad2deg(x):.2f}锟斤拷" ax.xaxis.set_major_formatter(FuncFormatter(rad2fmt)) #Adjust the sector window: you must call these AFTER setting the ticks, since setting the ticks #actually adjusts the theta range window. And it must be in degrees. ax.set_thetamin(np.rad2deg(minTheta)) ax.set_thetamax(np.rad2deg(maxTheta)) plt.show() </code> </pre> <P> <a href="https://i.stack.imgur.com/U1AZb.png" rel="nofollow noreferrer"> <img src =“https://i.stack.imgur.com/U1AZb.png”alt =“在此处输入图片说明”/> </A> </p> </DIV>

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1#
回复此人
12345 | 2019-08-31 10-32

<div class =“post-text”itemprop =“text”> <P> 或者，您可以使用 <a href="https://matplotlib.org/api/ticker_api.html#matplotlib.ticker.PercentFormatter" rel="nofollow noreferrer"> <code> PercentFormatter </code> </A> 。这里 <code> xmax </code> 是对应于100％的值。根据您转换为百分比，100％将对应于弧度值 <code> np.pi*100/180 </code> 。 </p> <P> 我通过评论突出显示了三行代码 <code> # </code> </p> <pre> <code> import numpy as np import matplotlib.pyplot as plt from matplotlib.ticker import PercentFormatter # <--- minTheta = 0.42; maxTheta = 0.55 fig = plt.figure() ax = fig.add_subplot(111, projection='polar') ticks = np.linspace(minTheta, maxTheta, 4) ax.set_xticks(ticks) ax.set_thetamin(np.rad2deg(minTheta)) ax.set_thetamax(np.rad2deg(maxTheta)) xmax = np.pi*100/180 # <--- ax.xaxis.set_major_formatter(PercentFormatter(xmax, decimals=2)) # <--- </code> </pre> <P> <a href="https://i.stack.imgur.com/onBmN.png" rel="nofollow noreferrer"> <img src =“https://i.stack.imgur.com/onBmN.png”alt =“在此处输入图片说明”/> </A> </p> </DIV>

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