PROSAGA码农传奇-Ruby-根据另一个数组中的顺序对数组数组进行排序

0# 咿呀哟 | 2019-08-31 10-32

1# 不浪漫 | 2019-08-31 10-32

<div class =“post-text”itemprop =“text”>
  <P>
    我假设：
  </p>
  <UL>
    <LI>
      每个元素的第一个元素
       <code>
        x
      </code>
       不一定是唯一的;
    </LI>
    <LI>
      所有元素
       <code>
        x
      </code>
       其第一个元素是相同的，其第一个元素是其成员
       <code>
        order_array
      </code>
       按照这些元素出现的顺序连续出现在返回的（已排序的）数组中
       <code>
        x
      </code>
      ;
    </LI>
    <LI>
      任何元素
       <code>
        x
      </code>
       其第一个元素不是。的成员
       <code>
        order_array
      </code>
       在第一个元素所在的所有元素之后出现在返回（已排序）数组中
       <code>
        sorted_array
      </code>
      ，并且所有这些元素按它们出现的顺序出现在返回的数组中（在结尾处）
       <code>
        x
      </code>
      ;和
    </LI>
    <LI>
      效率至关重要。
    </LI>
  </UL>
  <H1>
    <P>
    </p>
  </H1>
   <pre>
    <code>
      x = [
  ["ready", 5], ["shipped", 1], ["pending", 1], ["refunded", 1], ["originated", 3],
  ["delivered", 23], ["scheduled", 1], ["ready", 8], ["canceled", 51]
]

order_array = [
  "ready", "in_progress", "received", "shipped", "scheduled", "pick_up",
  "delivered", "canceled", "failed", "refunded", "refund_failed"
]

</code>
  </pre>
  <H1>
    <P>
    </p>
  </H1>
   <pre>
    <code>
      order_pos = order_array.each_with_object({}) { |word,h| h[word] = [] }
  #=> {"ready"=>[], "in_progress"=>[], "received"=>[], "shipped"=>[],
  #    "scheduled"=>[], "pick_up"=>[], "delivered"=>[], "canceled"=>[],
  #    "failed"=>[], "refunded"=>[], "refund_failed"=>[]} 
back = x.each_with_index.with_object([]) { |((word,v),i),back|
  order_pos.key?(word) ? (order_pos[word] << i) : back << [word,v] }
  #=> [["pending", 1], ["originated", 3]] 
order_pos.flat_map { |word,offsets| offsets.map { |i| x[i] } }.concat(back)
  #=> [["ready", 5], ["ready", 8], ["shipped", 1], ["scheduled", 1],
  #    ["delivered", 23], ["canceled", 51], ["refunded", 1], ["pending", 1],
  #    ["originated", 3]]

</code>
  </pre>
  <P>
    注意：
  </p>
   <pre>
    <code>
      order_pos
  #=> {"ready"=>[0, 7], "in_progress"=>[], "received"=>[], "shipped"=>[1],
  #    "scheduled"=>[6], "pick_up"==>[], "delivered"=>[5], "canceled"=>[8],
  #    "failed"=>[], "refunded"=>[3], "refund_failed"=>[]}

</code>
  </pre>
  <P>
    有必要初始化
     <code>
      order_pos
    </code>
     为了按键排序
     <code>
      order_arr
    </code>
    。这是Ruby 1.9中有争议的变化的一个例子，它保证了散列键将保持按键插入顺序。
  </p>
</DIV>

2# 十二* | 2019-08-31 10-32